ad(x²+ y²) - xy(a²+b²)
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Answered by
1
solve this problem as follows Bhai :
ab (x² + y²) – xy (a² + b²)
= abx² + aby² – a²xy – b²xy
= abx² – a²xy + aby² – b²xy
= ax (bx – ay) + by (ay – bx)
= ax (bx – ay) – by (bx – ay)
= (bx – ay (ax – by)
I hope you find this solution helpful
Answered by
0
Answer:
ab(x² + y²) −xy(a²+b²)
abx² + aby² -a²xy - b²xy
abx² + b²xy + aby² + a²xy
bx(ax−by)−ay(ax−by)
(ax−by)(bx−ay)
I hope this will help you mate
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