Math, asked by drona07, 4 months ago

Adam and Harry are travelling from city X to city Y in their respective cars. Adam reaches city Yin 3
hours whereas Harry reaches 45 minutes after Adam. If the speed of Harry's car is less than Adam's car by
12 km/hr, find the speed of Adam's car.​

Answers

Answered by kamarnathbhai
0

Answer:

Answer:

Distance b/w X and Y = Z km

Adam takes time = 3 hrs

Harry takes time = 45/60 = 0.75 hrs

Speed of Adam's Car = m

Speed of Harry's Car = m - 12

SpeedSpeed = \frac{Distance}{Time}

Time

Distance

For Adam's Car,

mm = \frac{Z}{3}

3

Z

∴ 3m = Z

For Harry's Car,

mm -− 1212 = \frac{Z}{0.75}

0.75

Z

mm -− 1212 = 4m4m

∴ m - 12 = 4m

∴ 3m = -12

∴ m = -4

But speed cam't be negative

∴ m = 4 km/h

∴ Speed of Adam's Car = m = 4 km/h

Answered by bhavikakaushik998
0

Answer:

4 km/h

Step-by-step explanation:

Distance b/w X and Y = Z km

Adam takes time = 3 hrs

Harry takes time = 45/60 = 0.75 hrs

Speed of Adam's Car = m

Speed of Harry's Car = m - 12

Speed = \frac{Distance}{Time}

Time

Distance

For Adam's Car,

mm = \frac{Z}{3}

3

Z

∴ 3m = Z

For Harry's Car,

mm -− 1212 = \frac{Z}{0.75}

0.75

Z

mm -− 1212 = 4m4m

∴ m - 12 = 4m

∴ 3m = -12

∴ m = -4

But speed can't be negative

∴ m = 4 km/h

∴ Speed of Adam's Car = m = 4 km/h

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