Question

Adam has $2.15 in nickels, dimes and quarters in his pocket. If the number of dimes is 4 less than the number of nickels, and 5 more than the number of quarters, then how many of each type of coin does he have?

Answer 1

Answer:

There are 8 dimes, 12 nickels and 3 quarters

Step-by-step explanation:

Define x:

Let x be the number of dimes

Number of nickels = x + 4

Number of quarters = x - 5

Solve x:

Total value is 2.15

(Dime = $0.10, Nickels = $0.05, Quarters = $0.25)

0.1x + 0.05(x + 4) + 0.25(x - 5) = 2.15

0.1x + 0.05x + 0.2 + 0.25x - 1.25 = 2.15

0.4x = 3.2

x = 8

Find the number of coins:

Dime = x = 8

Nickels = x - 4 = 8 + 4 = 12

Quarters = x - 5 = 8 - 5 = 3

Answer: There are 8 dimes, 12 nickels and 3 quarters