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The side BC of ABC is produced to a point D. The bisector of ZA meets
the side BC in P. If ZABC = 30°, ZACD = 110°, find ZAPC.
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Answer:
Bisector divides angle in two equal parts
so angle BAP = angle PAC (Given angle BAP = 30°)
sum of opposite angle is equal to exterior angle
therefore
angle APC+ angle PAC = angle ACD
angle APC = 110° - angle APC
= 110° - 30°
= 80°
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