Question

ADC is a triangle and a point B is on AC .AB=3BC . area of triangle BCD is 10cm^2 .Find area of triangles ABD and ADC in cm^2. ​

Answer 1

Answer:

solved

Step-by-step explanation:

AB=3BC , let BC = B , AB = 3B

area of triangle BCD = BH/2 = 10cm² , BH =20

area of triangles ABD = 3/2 x BH = 30 cm²

area of triangles  ADC = 2BH = 40 cm²

Answer 2

Step-by-step explanation:

Answer

Given : 9(2a−b)

2

−4(2a−b)−13

Let us consider 2a−b=c

So we get,

=9c

2

−4c−13

We can further write it as

=9c

2

−13c+9c−13

By taking out the common terms

=c(9c−13)+1(9c−13)

=(c+1)(9c−13)

Let us replace c by 2a−b

so we get

9(2a−b)

2

−4(2a−b)−13

Then,

=((2a−b)+1)(9(2a−b)−13)

∴9(2a−b)

2

−4(2a−b)−13=(2a−b+1)(18a−9b−13