Math, asked by ash9863, 1 year ago

Add 1) 2x( z-x-y ) and 2y(z-y-x)​

Answers

Answered by riya1504
0

= 2x(z-x-y) + 2y(z-y-x)

= 2xz - 2x² - 2xy + 2yz - 2y² - 2xy

= 2xz - 2x² - 2xy - 2xy + 2yz - 2y²

= 2xz - 2x² - 4xy + 2yz - 2y²

Thus, answer is 2xz - 2x² - 4xy + 2yz - 2y².

Answered by piyushgupta2301
0

(2x+2y)(z+z-x-x-y-y)

(2x+2y)(2z-2x-2y)

2(x+y)(z-x-y)

2(xz-x^2-xy+yz-xy-y^2)

2(x2-y2-2xy+xz+yz)

2(x3-y3-z3)

HOPE IT HELPS YOU......

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