Question

Add :
1 3by 4 and 5by 3
​

Answer 1

$13 \div 4 + 5 \div 3$

$lcm \: of \: 4 \: and \: 3 \: is \: 12.$

$(39 + 20) \div 12$

$59 \div 12$

$hope \: it \: will \: help \: you$

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Answer 2

We need to add ⇒ $1\frac{3}{4}+\frac{5}{3}$

Step 1: Convert the mixed fraction to improper fraction.

To do so we need to multiply the whole number part to the denominator and then add the product to the numerator. Then the number we get will be the numerator and the denominator part will the same as in the fractional part of the mixed fraction.

$1\frac{3}{4}=\frac{7}{4}$

We need to add ⇒ $\frac{7}{4} +\frac{5}{3}$

Step 2: The fractions have, unlike denominators. So we need, find the LCM (Least Common Multiple) and rewrite the fractions with the common denominator.

LCM of the denominator (3 and 4) is 12.

Step 3: Multiply both the numerator and denominator of each fraction by the number that makes its denominator equal to the LCM.

$\frac{7*3}{4*3}+\frac{5*4}{3*4}$

$\frac{21}{12} +\frac{20}{12}$

Step 4: The two fractions now have like denominators so you can add the numerators.

$\frac{21+20}{12}=\frac{41}{12}$

Step 5: Reduce to lowest form but this cannot be reduced so we skip this step.

Step 6: Convert the improper fraction to mixed fraction (optional).

For this, we need to divide the numerator by the denominator.

The quotient (answer) will be the whole number part. The remainder will be the numerator of the fractional part. The divisor (the other number we divide with) will be the denominator part of the fractional part.

$\frac{41}{12}=3\frac{5}{12}$

∴ $1\frac{3}{4}+\frac{5}{3}=\frac{41}{12} \ or \ 3\frac{5}{12}$.