Add 1/root2+1/root2 plz explain
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Hello friend!!
The answer is...
![1 \sqrt{2} + 1 \sqrt{2} \\ = > 2 \sqrt{2} 1 \sqrt{2} + 1 \sqrt{2} \\ = > 2 \sqrt{2}](https://tex.z-dn.net/?f=1+%5Csqrt%7B2%7D++%2B+1+%5Csqrt%7B2%7D+++%5C%5C++%3D++%26gt%3B+2+%5Csqrt%7B2%7D+)
I hope it helps you...
The answer is...
I hope it helps you...
vijaykumar2917:
hi friend
Answered by
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hope it will help u.....
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