Question

Add : 12y3
+ 20y2 - 28y and 2y3- 8y2
+ 10
please show calculations​

Answer 1

12y³

+20y²

32y5

- 28y

4y6

and

16y5

Answer is 4y6 and 16y5

Answer 2

Given

We have given terms : 12y³+20y²-28y and 2y³-8y²+10

What to do

We have to add the terms

$\sf\huge {\underline{\underline{{Solution}}}}$

Concept:

Terms of same degree and same Variable or we can say that only like terms can be added or subtracted in an algebraic equations.

12y³+20y²-28y and 2y³-8y²+10

Solving for y³

=> 12y³+2y³= 14y³

Solving for y²

12y³+20y²-28y and 2y³-8y²+10

=> 20y²-8y²= 12y²

solving for y

12y³+20y²-28y and 2y³-8y²+10

No like term found for y and constant alone .

So,our final Equation is : 14y³+12y²-28y+10