Add : 2×(2-×-y) and zy(z-y-×)
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2×(2-x-y)
=4-2x-2y
zy (z-y-x)
=z²y - zy² - xyz
=4-2x-2y
zy (z-y-x)
=z²y - zy² - xyz
Answered by
0
Answer:
Step-by-step explanation:
2×(2-x-y)
=4-2x-2y
zy (z-y-x)
=z²y - zy² - xyz
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