Add (2√3+5√5-7√7) and (3√5-√3+√7)
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Answered by
20
Hey.......!!! here is ur answer........☺️☺️☺️
Given that the two irrational numbers,
(2√3+5√5–7√7) and (3√5–√3+√7)
On adding.......
(2√3+5√5–7√7) + (3√5–√3+√7)
=>2√3+5√5–7√7+3√5–√3+√7
=>2√3–√3+5√5+3√5–7√7+√7
=>√3+8√5–6√7 <<<<<Ans.
I hope it will help you........✌️✌️✌️
Given that the two irrational numbers,
(2√3+5√5–7√7) and (3√5–√3+√7)
On adding.......
(2√3+5√5–7√7) + (3√5–√3+√7)
=>2√3+5√5–7√7+3√5–√3+√7
=>2√3–√3+5√5+3√5–7√7+√7
=>√3+8√5–6√7 <<<<<Ans.
I hope it will help you........✌️✌️✌️
garima81:
thank you for helping
Answered by
1
(2√3+5√5-7√7)+ (3√5-√3+√7) = √3 + 8√5 - 6√7.
Given:
(2√3+5√5-7√7) and (3√5-√3+√7)
To find:
Add this
Solution:
We have to add the given numbers
To add them we will put same roots together
(2√3+5√5-7√7) + (3√5-√3+√7)
= 2√3 - √3 + 5√5 + 3√5 - 7√7 + √7
= √3 + 8√5 - 6√7
The same roots are added or subtracted together.
Hence, the answer is √3 + 8√5 - 6√7.
#SPJ2
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