Math, asked by shobhit2732006, 10 months ago

add (2/3 root 7 -1/2 root 2 +6 root 11) and (1/3 root 7 +3/2 root 2 - root 11)

Answers

Answered by tennetiraj86
43

Answer:

answer for the given problem is given

Attachments:
Answered by sourasghotekar123
2

Answer:

\sqrt{7}+\sqrt{2}+5(\sqrt{11})

Step-by-step explanation:

Given that

  (\frac{2}{3}(\sqrt{7})-\frac{1}{2}(\sqrt{2})+(6)\sqrt{11}    \\ and \frac{1}{3}(\sqrt{7})+\frac{3}{2}(\sqrt{2})-\sqrt{11}

on adding them

  \frac{2}{3} }(\sqrt{7})-\frac{1}{2}(\sqrt{2})+6(\sqrt{11})+(\frac{1}{3}(\sqrt{7})+\frac{3}{2}(\sqrt{2})-\sqrt{11}

  \frac{2}{3}(\sqrt{7}+\frac{1}{3}(\sqrt{7})+\frac{-1}{2}(\sqrt{2})+\frac{3}{2}(\sqrt{2})+6(\sqrt{11-\sqrt{11} )     (\frac{2}{3} +\frac{1}{3}) \sqrt{7}+(\frac{3}{2}-\frac{1}{2})\sqrt{2}+(6-1)\sqrt{11}

\frac{3}{3}(\sqrt{7})+\frac{2}{2}(\sqrt{2})+5(\sqrt{11})

\sqrt{7}+\sqrt{2}+5(\sqrt{11})

The project code is #SPJ2

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