Question

Add 23/7 to the difference of 4 and 7/3

Answer 1

$Add \: \frac{23}{7} \:to \:the \: difference \:of$

$4 \:and \: \frac{7}{3}$

$= \frac{23}{7} + \Big( 4 - \frac{7}{3}\Big)$

$= \frac{23}{7} + \Big( \frac{12-7}{3}\Big)$

$= \frac{23}{7} + \frac{5}{3}$

$= \frac{69+35}{21}$

$= \frac{410}{21}$

Therefore.,

$\red{Add \: \frac{23}{7} \:to \:the \: difference \:of}$

$\red{4 \:and \: \frac{7}{3} }$

$\green { = \frac{410}{21}}$

•••♪

Answer 2

Answer:

A.T. Q ( according to question )

$\\ \frac{23}{7} + (4 - \frac{7}{3} ) \\ \frac{23}{7} + ( \frac{4 \times 3}{1 \times 3} - \frac{7}{3} ) \\ \frac{23}{7} + ( \frac{12 - 7}{3}) \\ \frac{23}{7} + \frac{5}{3} \\ \frac{23 \times 3}{7 \times 3} + \frac{5 \times 7}{3 \times 7} \\ \frac{69 + 35}{21} \\ = \frac{104}{21} \: ans$

I hope it will help