Question

Add : 2a(-4a+6b²+3ab²) and 6a²(b²+1) and evaluate for a=-1 and b=2​

Answer 1

Step-by-step explanation:

2(1)[-4(1)+6(2)^2+3(1)(2)^2

2(-4+24+12)

32×2=64

6(1)^2(4+1)

6×5=30