Question

add 2a (a+b-c) and 3b (a-b-c)​

Answer 1

Answer:

Step-by-step explanation:

2a (a+b-c) + 3b (a-b-c)​

2a² + 2ab - 2ac + 3ab - 3b² - 3bc

2a² - 3b² + 5ab - 2ac - 3bc

Answer 2

Step-by-step explanation:

= 2a (a+b-c) +3b (a-b-c)

= opening the brackets

$= > 2 {a}^{2 } + 2ab - 2ac + 3ba - 3 {b}^{2} - 3bc$

$= > 2 {a}^{2} + 2ab + 3ab - 2ac - {3b}^{2} - 3bc$

$= > 2 {a}^{2} + 5ab - 2ac - 3 {b}^{2} - 3bc \: \: ans..$

Hope it helps you...