Question

Add (2a2 + 5b2 – 4ab) and (6ab – 4a2 – 11b2)

Answer 1

Step-by-step explanation:

x = 4a2 + b2 – 6ab

y = 3b2 – 2a2 + 8ab

z = 6a2 + 8b2 – 6ab

(i) x + y + z = 4a2 + b2 – 6ab + 3b2 – 2a2 + 8ab + 6a2 + 8b2 – 6ab

= 4a2 – 2a2 + 6a2 + b2 + 3b2 + 8b2 – 6ab + 8ab – 6ab

= 10a2 – 2a2 + 12b2 – 12ab + 8ab

= 8a2 + 12b2 – 4ab

(ii) x – y – z = (4a2 + b2 – 6ab) – (3b2 – 2a2 + 8ab) – (6a2 + 8b2 – 6ab)

= 4a2 + b2 – 6ab – 3b2 + 2a2 – 8ab – 6a2 – 8b2 + 6ab

= 4a2 + 2a2 – 6a2 + b2 – 3b2 – 8b2 – 6ab – 8ab + 6ab

= 6a2 – 6a2 + b2 – 11b2 – 14ab + 6ab

= -10b2 – 8ab

Answer 2

Answer:

2a²-4a²+5b²-11b²-4ab+6ab

-2a²-6b²+2ab