Math, asked by dsilvamonica066, 6 months ago

Add: 2c (d-c-a) and 2a Cd-a-c)

Answers

Answered by VarunTejdharavath

0

Answer:

2c (d-c-a) and 2a (d-a-c)

2cd-2c^2-2ac and 2ad-2a^2-2ac

2cd-2c^2-2ac +(2ad-2a^2-2ac)

2cd-2c^2-2ac+2ad-2a^2-2ac

= 2cd-2c^2-2a^2-4ac+2ad

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