Question

add

2c2-3c+6, -2c+7c2-3, c-3c2 and -4+c2

Answer 1

Step-by-step explanation:

$\: \: \: \: {2c}^{2} - 3c + 6 \\ \: \: \: \: 7 {c}^{2} - 2c - 3 \\ - 3 {c}^{2} + c + 0 \\ \: \: \: \: {c}^{2} + 0c - 4 \\ ........................ \\ \: \: \: \: 7 {c}^{2} - 4c - 1$

your answer is ⤵️

$7 {c}^{2} - 4c - 1$

please Mark as brainly answer

Answer 2

Answer :

= $(2{c}^{2} - {3}{c} + 6 ) + ({-2}{c} + {7c}^{2} - 3 ) + ( c - {3c}^{2} ) + ( -4 + {c}^{2})$

= $( {9c}^{2} -5c + 3) + ( c - {3c}^{2} ) + ( -4 + {c}^{2})$

= $( {6c}^{2} -4c+ 3) + ( -4 + {c}^{2})$

= $({7c}^{2} -4c -1)$

$\rule{250}{2}$