add 2x -3y +5z and 6y-2z +4x
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Answered by
2
2x-3y+5z+6y-2z+4x
= 6x+3y+3z
=3(2x+y+z)
Answered by
1
2x−3y+5z+6y−2z+4x
=2x+−3y+5z+6y+−2z+4x
=2x+−3y+5z+6y+−2z+4x
=(2x+4x)+(−3y+6y)+(5z+−2z)
=6x+3y+3z
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