add 2x(z-x-y)and 2y(z-y-x)
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Answered by
112
2x(z-x-y)and 2y(z-y-x)
=2xz-2x(squqre)-2xy+2yz-2y(square)-2xy
=2xz-2x(squqre)-2xy-2xy+2yz-2y(square)
=2xz-2x(square)-4xy+2yz-2y(square)
=2xz-2x(squqre)-2xy+2yz-2y(square)-2xy
=2xz-2x(squqre)-2xy-2xy+2yz-2y(square)
=2xz-2x(square)-4xy+2yz-2y(square)
Answered by
16
2x(z-x-y) + 2y(z-y-x)
=2xz - 2xsq + 2xy + 2yz - 2ysq - 2xy
= 2xz - 2xsq + 2yz - 2xy..
Where is sq it means square I write the short form ...
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