Math, asked by Anonymous, 5 months ago

add : 2x(z-x-y) and 2y(z-y-x​

Answers

Answered by ankitamaurya1196
2

Step-by-step explanation:

= (2xz - 2x2 - 2xy) + (2yz - 2y2 - 2xy)

= 2xz - 2x2 - 2xy + 2yz - 2y2 - 2xy

= 2x2 - 2y2 + 2xz + 2yz - 2xy - 2xy

= 2x2 - 2y2 + 2xz + 2yz - 4xy

Hope you got it...

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