Question

Add: (3/5-√3) + (2/5+√3)​

Answer 1

Answer:

(3/5-√3/1)+(2/5+√3/1)

= 3-5√3/5)+(2+5√3/5)

= 3-5√3+2+5√3/5

= 5-0/5

= 5/5

= 1

thank u

Answer 2

$\huge {\boxed {\mathbb {QUESTION}}}$

$Add$

$(\frac{3}{5-\sqrt{3}})+(\frac{2}{5-\sqrt{3}})$

$\huge {\boxed {\mathbb {ANSWER}}}$

$\implies (\frac{3}{5-\sqrt{3}})+(\frac{2}{5-\sqrt{3}})$

$\implies \frac{3(5+\sqrt{3})+2(5-\sqrt{3})}{(5-\sqrt{3})(5+\sqrt{3})}$

$\implies \frac{15+3\sqrt{3}+10-2\sqrt{3}}{25-3}$

$\implies{\boxed {\boxed {\frac{25+sqrt{3}}{22}}}}$

$\huge {\boxed {\mathbb {HOPE \:IT \:HELPS \:YOU}}}$

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$\huge {\boxed {\mathbb {EXTRA\:INFORMATION}}}$$Rationalising \:the\:denominator$

• $To\: rationalize\: the\: denominator\:, multiply\\ both\: the\: numerator\: and\: the\: denominator\:\\ by\: the\: conjugate\: of\: the\\ denominator.$
• $Remember\: to \:find \:the\: conjugate\: we\\ have\: to\: change\: the\: sign\: between\: the\\ two\: terms.$

${\mathbb{\colorbox {orange} {\boxed{\boxed{\boxed{\boxed{\boxed{\colorbox {lime} {\boxed{\boxed{\boxed{\boxed{\boxed{\colorbox {aqua} {@suraj5070}}}}}}}}}}}}}}}$