Add: 3a – 2b, b + c, 2c – d, a – b + d and 5a – 2b + 3c
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add 3a+4b−2c and −6a−2b+3c
(3a+4b−2c)+(−ba−2b+3c)
⇒(3a−6a)+(4b−2b)+(3c−2c)
⇒
−3a+2b+c
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this is the correct answer I hope it helps you to solve your question dear
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