Question

Add:3a(a-b+c),2b(a-b+c)

Answer 1

$\textbf{SOLUTION}$

$\textbf{we have to add}$

$\mathbf{3a( a - b + c),2b(a - b +c)}$

$\textbf{So we have}$

$\mathbf{3a (a - b + c) + 2b (a - b + c)}$

$\mathbf{= 3a^2 - 3ab + 3ac + 2ab - 2b^2 + 2bc}$

$\mathbf{= 3a^2 - 2b^2 - 3ab + 2ab + 3ac + 2bc}$

$\mathbf{= a^2 - ab + 3ac + 2bc}$

$\huge{THANKS}$

Have a colossal day ahead

$\Huge\mathfrak{Be BrainlY}$

Answer 2

$<b > Ello!!$

Here's your answer

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To add ,

3a ( a + b + c ) and 2b ( a - b + c )

Now ,

3a ( a + b + c ) + 2b ( a - b + c )

= 3a² + 3ab + 3ac + 2ab - 2b² + 2bc

= 3a² - 2b² + 5ab + 3ac + 2bc [ ★ Required answer ]

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Hope it helps!!