Question

Add:
3a(a-b+c) , 3c (2a + 2b)​

Answer 1

Answer:

1. Here, 3a(2b + 5c) = 6ab + 15ac.

2. 3c(2a + 2b) = 6ac + 6bc.

3. Hence the two polynomials to be added are 6ab + 15ac and 6ac + 6bc.

4. he result is as follows 6ab + 21ac + 6bc.

Step-by-step explanation:

Answer 2

First equation,
3a(a-b+c)
=3a*2-3ab+3ac

Now equation 2
3c(2a+2b)
=6ac+6bc

Now adding both we get
(3a*2-3ab+3a)+(6ac+6bc)
=3a*2 -3ab +3ac + 6ac +6bc
=3(a*2 - ab +3ac +2bc)
= a*2 - ab +3ac +2bc
Hope it helps