Add : 3a ( b – a – c ) and 3b ( c – b – a)
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Answer:
3a(a−b+c)+2b(a−b+c)
=(3a+2b)(a−b+c)
=3a
2
−3ab+3ac+2ab−2b
2
+2bc
=3a
2
−ab−2b
2
+3ac+2bc
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