Question

add
3ab + 2ac – 3a and -6ac + 2b + 3ab

Answer 1

(3ab+2ac-3a) + (-6ac+2b+3ab)
= 3ab + 2ac - 3a - 6ac + 2b + 3ab
= 3ab + 3ab + 2ac - 6ac - 3a + 2b
= 6ab - 4ac - 3a + 2b.

Answer 2

Answer:3ab+2c-3=a(3b+2c-3)

-6ac+2b+3ab=a(-6c+2b+3b)

Step-by-step explanation:In first one,

Taking a as common we got a(3b+2c-3).

Similarly in second one taking a as common we got a(-6c+2b+3b)..

Hope it will help u