Add 3ala -b+ c) and 2bla- b+ c)
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It would be 3a^2l + 2abl-2b+2c
Step-by-step explanation: Since 3ala cannot be added with 2bla then first you would write 3ala+2bla BUT since there are 2 a's in 3ala it would be 3a^2l then plus 2bla. Then -b-b= -2b. Next c+c= 2c. So it would be 3a^2l+2bla-2b+2c. You should also arrange the variables in 2bla to be 2abl. So technically the right answer (simplified and in correct order) would be 3a^2l + 2abl-2b+2c.
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