Question

Add : 4ab - 5bc + 7ca , - 3ab + 2bc - 3ca , 5ab - 3bc + 4ca​

Answer 1

Step-by-step explanation:

Given 4ab – 5bc + 7ca, –3ab + 2bc – 3ca and 5ab – 3bc + 4ca

= (4ab – 5bc + 7ca) + (–3ab + 2bc – 3ca) + (5ab – 3bc + 4ca)

Collecting positive and negative like terms together, we get

= 4ab – 3ab + 5ab – 5bc + 2bc – 3bc + 7ca – 3ca + 4ca = 9ab – 3ab – 8bc + 2bc + 11ca – 3ca

= 6ab – 6bc + 8ca

Answer 2

4ab-5bc+7ca+(-3ab+2bc-3ca) +5ab-3bc+4ca

=6ab-6bc+8ca