Question

add 4t(3t²-5t-6) and 5(t³-2t²+15)​

Answer 1

Answer:

$4t(3t^{2} -5t-6)+5(t^{3} -2t^{2} +15)$ = $17t^{3} -30t^{2} -24t+75$

Step-by-step explanation:

Given : $4t(3t^{2} -5t-6)+5(t^{3} -2t^{2} +15)$

To find : Addition of the given expression

Solution :

• Given expression is,  

      $4t(3t^{2} -5t-6)+5(t^{3} -2t^{2} +15)$

• In order to add this expression, we should first open the brackets, we get

      $4t(3t^{2} -5t-6)+5(t^{3} -2t^{2} +15)$ = $12t^{3}-20t^{2}-24t+5t^{3}-10t^{2}+75$

• Now,adding the terms with equal variables and exponentials, we get

                            $= 17t^{3} -30t^{2}-24t+75$

• ∴ $4t(3t^{2} -5t-6)+5(t^{3} -2t^{2} +15)$ = $17t^{3}-30t^{2} -24t+75$