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4x²y ,(-2xy²),3x²y and 8xy²
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Answered by
1
Answer:
Solution:
The H.C.F. of numerical coefficients = The H.C.F. of 4 and 6.
Since, 4 = 2 × 2 = 22 and 6 = 2 × 3 = 21 × 31
Therefore, the H.C.F. of 4 and 6 is 2
Answered by
2
Answer:
7x²y+6xy²
Step-by-step explanation:
4x²y+(-2xy²)+3x²y+8xy²
4x²y-2xy²+3x²y+8xy²
4x²y+3x²y+8xy²-2xy²
7x²y+6xy²
hope this helps you
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