Math, asked by rajeswarsubudhi06, 3 months ago

Add 4y (3 y ^2+ 5 y - 7) and 2 (y ^2- 4 y ^3+ 5) *​

Answers

Answered by ritatiwari1234321
4

Answer:

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Answered by prachigupta431
0

Answer:

3(y−5)÷4−4y=3−(y−3)÷2=)3(y−5)−16y=12−2(y−3)=)3y−15−16y=12−2y+6=)−13y−15=−2y+18=)−11y=33=)−y=1133=)y=−3

\huge{\red{\boxed{\boxed{\green{\underline{\sf{\green{y=-3}}}}}}}}y=−3

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