Math, asked by sharmabhushan187, 2 months ago

add
4y (3y

2 + 5y – 7) and 2 (y

3– 4y

2+ 5)​

Answers

Answered by Anonymous
4

4y(3y^2 + 5y - 7) + 2(y^3 - 4y^2 + 5)

=> 12y^3 + 20y^2 - 28y + 2y^3 - 8y^2 + 10

=> 12y^3 + 2y^3 + 20y^2 - 8y^2 - 28y + 10

=> 14y^3 + 12y^2 - 28y + 10 ✔

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