Question

add : 4y ( 3y^2 + 5y - 7) and 2 ( y^3 - 4y^2 +5) from ch 9
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Answer 1

Answer:

We have,

4y(3y

2

+5y−7)+2(y

3

−4y

2

+5)

⇒12y

3

+20y

2

−28y+2y

3

−8y

2

+10

⇒14y

3

+12y

2

−28y+10

Hence, this is the answer.