Question

add 4y(y3-4y2+5) nd 2(3y2+5y-7)​

Answer 1

Answer:

( 2y³ -8y² + 12xy³ + 20xy² -28xy +10)

Step-by-step explanation:

we have to add

4xy(3y²+5y-7) and 2(y³-4y²+5)

solution

4xy(3y²+5y-7) + 2(y³-4y²+5)

= (12xy³ + 20xy² -28xy )  + ( 2y³ -8y² +10)

=( 2y³ -8y² + 12xy³ + 20xy² -28xy +10) answer

Answer 2

Step-by-step explanation:

$4y(3y - 4 {y}^{2} + 5) + 2(3 {y}^{2} + 5y - 7) \\ = 12 {y}^{2} - 16 {y}^{3} + 20y + 6 {y}^{2} + 10y - 14 \\ = - 16 {y}^{3} + 18 {y}^{2} + 30y - 14$

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