Add: 6a - a², -3a² + 8a and -15a + a²
Answers
Answer:
Changes made to your input should not affect the solution:
(1): "a2" was replaced by "a^2".
STEP
1
:
Trying to factor by splitting the middle term
1.1 Factoring a2+6a+8
The first term is, a2 its coefficient is 1 .
The middle term is, +6a its coefficient is 6 .
The last term, "the constant", is +8
Step-1 : Multiply the coefficient of the first term by the constant 1 • 8 = 8
Step-2 : Find two factors of 8 whose sum equals the coefficient of the middle term, which is 6 .
-8 + -1 = -9
-4 + -2 = -6
-2 + -4 = -6
-1 + -8 = -9
1 + 8 = 9
2 + 4 = 6 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, 2 and 4
a2 + 2a + 4a + 8
Step-4 : Add up the first 2 terms, pulling out like factors :
a • (a+2)
Add up the last 2 terms, pulling out common factors :
4 • (a+2)
Step-5 : Add up the four terms of step 4 :
(a+4) • (a+2)
Which is the desired factorization
Final result :
(a + 4) • (a + 2)
Step-by-step explanation:
Answer:
- 3a^2 - a
Step-by-step explanation:
6a - a^2 -3a^2 +8 -15a + a^2
-3a^2 - a
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