Add:
6m²n +4mn
an² +5,
n²- nm² +3,
mn
3n² – amin-4.
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The three terms are
(6m²n + 4mn - 2n² + 5),
(n² - nm² + 3) and
(mn - 3n² - 2m²n - 4)
So, the required sum be
= (6m²n + 4mn - 2n² + 5)
+ (n² - nm² + 3)
+ (mn - 3n² - 2m²n - 4)
= (6 - 2)m²n + (4 + 1)mn
+ (- 2 + 1 - 3)n² - nm²
+ (5 + 3 - 4)
= 4m²n + 5mn - 4n² - nm² + 4
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