Add 7/9 and -12/9
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Answers
Step-by-step explanation:
\large \dag† Question :-
A shopkeeper bought two items at ₹ 450 each. He sold one at loss of 10%. At what price should he sell the other so as to gain 20% on the whole transaction?
\large \dag† Answer :-
\begin{gathered}\red\dashrightarrow\underline{\underline{\sf \green{He \: should \: Sell \: other \: item \: at \: ₹675}} }\\ \end{gathered}
⇢
HeshouldSellotheritemat₹675
\large \dag† Step by step Explanation :-
Let the shopkeeper sold 2nd item for ₹ x
According To Question total CP of both items is 450 × 2 = \large \green{ \bf ₹ 900 } {}^{ \red\bigstar}₹900
★
We Know that
\bf \red\bigstar \: \: \orange{ \underbrace{ \underline{ SP = \frac{100 - Lost\%}{100} \times CP}}}★
SP=
100
100−Lost%
×CP
And,
\bf \red\bigstar \: \: \orange{ \underbrace{ \underline{ SP = \frac{100 + Gain\%}{100} \times CP}}}★
SP=
100
100+Gain%
×CP
❒ As first item is sold at a loss of 10% :
Selling Price of 1st item will be
\begin{gathered} \maltese \: \rm SP_1 = \frac{100 - 10}{100} \times 450 \\ \end{gathered}
✠SP
1
=
100
100−10
×450
\begin{gathered}:\longmapsto \rm SP_1 = \frac{90}{100} \times 450 \\ \end{gathered}
:⟼SP
1
=
100
90
×450
\begin{gathered}:\longmapsto \rm SP_1 = 9 \times 45 \\ \end{gathered}
:⟼SP
1
=9×45
\purple{ \large :\longmapsto \underline {\boxed{{\bf SP_1 =₹\: 405} }}}:⟼
SP
1
=₹405
❒ According To Question Shopkeeper gain 20% on the whole transaction :
So Selling Price of Both Items should be
\begin{gathered} \rm \maltese \: \: SP = \frac{100 + 20}{100} \times 900 \\ \end{gathered}
✠SP=
100
100+20
×900
\begin{gathered}:\longmapsto \rm SP = \frac{120}{100} \times 900 \\ \end{gathered}
:⟼SP=
100
120
×900
\begin{gathered}:\longmapsto \rm SP = 120 \times 9 \\ \end{gathered}
:⟼SP=120×9
\purple{ \large :\longmapsto \underline {\boxed{{\bf SP = ₹ 1080} }}}:⟼
SP=₹1080
✧ As a shopkeeper loss 10% for selling first item and get 20% on whole transaction :
Therefore Selling Price of 2nd Item will be
\begin{gathered}\large \bf \red\bigstar \: \: \orange{ \underbrace{ \underline{ SP_2=SP-SP_1 }}} \\ \end{gathered}
★
SP
2
=SP−SP
1
⏩ Putting Values In above Expression ;
\begin{gathered}:\longmapsto \rm SP_2 = 1080 - 405 \\ \end{gathered}
:⟼SP
2
=1080−405
\purple{ \large :\longmapsto \underline {\boxed{{\bf SP_2 = ₹ 675} }}}:⟼
SP
2
=₹675
Therefore,
\begin{gathered}\blue\dashrightarrow\underline{\pink{\underline{\frak{\pmb{\text S P \: of \: other \: item \: should \: be \: ₹ 675 }}}}} \\ \end{gathered}
⇢
SPofotheritemshouldbe₹675
SPofotheritemshouldbe₹675