Question

Add (7x2 ─ 8) + (3x2 + 1).


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Answer 1

Step-by-step explanation:

(7×2-8)+(3×2+1)

(14-8)+(6+1)

6+7

13

Answer 2

Answer:

∴ The value of $(7x^{2} -8)+(3x^{2} +1)$ is $10x^{2} -7$.  

Step-by-step explanation:

• In context to question asked,
• We have to find the value of $(7x^{2} -8)+(3x^{2} +1)$.
• Addition is one of the important arithmetic operation of mathematics among division, multiplication, addition and subtraction.
• To find the value of $(7x^{2} -8)+(3x^{2} +1)$, we have to first open the brackets.
• So, the given expression is,

        $(7x^{2} -8)+(3x^{2} +1)$ $= 7x^{2} -8+3x^{2} +1$

• Now, add the terms with same variable with power and constant terms, we get

                                  = $10x^{2} -7$

• ∴ The value of $(7x^{2} -8)+(3x^{2} +1)$ is $10x^{2} -7$.