Question

Add a-2c+b,-a+b,ca-4c+ b

Answer 1

Step-by-step explanation:

Given 3a+b+2c=3,a+3b+2c=1, how do find 2a+c?

The most obvious part of this problem is the fact that any solution will require getting rid of b.

One way to do so is to multiply equation 1 by 3 and then subtract equation 2 from that:

9a + 3b + 6c = 9

a + 3b + 2c = 1

Subtracting the bottom from the top gives us

8a + 0b + 4c = 8

or

8a + 4c = 8

Dividing this equation by 4 gives the answer:

2a + c = 2

Answer 2

a- 2c + b + ( - a + b ) + ac - 4c + b

a-2 c + b - a + b + ac - 4c - 4c + b

2c + 3b + ac - 8c

3b + ac - 6c