Question

add a question tag 1. there was no response despite several reminders

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Answer 1

Explanation:

L.H.S

I=∫secxdx

I=∫

tanx+secx

secx(tanx+secx)

dx

I=∫

tanx+secx

secxtanx+sec

2

x

dx

Let t=tanx+secx

dt=(sec

2

x+secxtanx)dx

Therefore,

I=∫

t

1

dx

I=logt+C

I=log(tanx+secx)+C

Hence, this is the answer

Answer 2

Answer:

There was no response despite several reminders, was there?

Explanation:

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