add a velocity of 30 m/s towards east to a velocity of 40m/s towards north ,calculate magnitude and direction with respect to East
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Magnitude of the resultant:R=v12+v22−−−−−−−√ =(30)2+(40)2−−−−−−−−−−√ =50 m/s Direction of the resultant with east:θ=tan−1(v2v1) =tan−1(4030) =53.13o
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tanya591:
sry the answer is 53.13°
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