Math, asked by sunitamahankuda553, 4 months ago

Add:
(i)4a²b, 3²b,- a² b ,8 a²b​

Answers

Answered by nightread
0

Answer:

4a²b + 3²b + (- a²b) + 8a²b

= 4a²b + 8a²b - a²b + 3²b

= 12a²b - a²b + 3²b

= 11a²b + 3a²b

Hope it helps

Answered by pgpc
0

4a^2b+3^2b+(-a^2b) +8a^2b

4a^2b+3^2b-a^2b) +8a^2b

4a^2b-a^2b+8a^2b +3^2b

(4-1+8)a^2b+3^2b

11a^2b+3^2b

11a^2b+3^2b

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