Question

Add.
i) 6p + 139; 12p + 39
ii) 6a + 3b + 5c; 9a + 6b+
iii) 3x? - 10y + 8; 6y + 3
iv)-2y? + 6y-10; 2y? - 3y +
Subtract​

Answer 1

i.

$= (6p + 139) + (12p + 39) \\ = 6p + 12p + 139 + 39 \\ = 18p + 178 \\ = 18(p + 11)$

ii.

$= 6a + 3b + 5c + 9a + 6b \\ = 15a + 9b + 5c$

iii.

$= 3x - 10y + 8 + 6y + 3 \\ = 3x - 4y + 11$

iv.

= -2y?+6y-10+2y?-3y

=0+3y+10

=3y+10