Question

add: i) a²+ab-4b, b²+4b-ab, c²+4a-4b​

Answer 1

$\displaystyle\blue{\underline{\underline{Solution}}}$

The required answer is

$= \: (a²+ab-4b) + ( b²+4b-ab) + (c²+4a-4b)$

$= a²+ab-4b + b²+4b-ab + c²+4a-4b$

$= a² + b² + c²+4a-4b$

Answer 2

Answer:

by cutting the terms like 4b is cutted by -4b so we can solve it

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