Question

Add: i) a²+ab-4b, b²+4b-ab, c²+4a-4b

Answer 1

Step-by-step explanation:

The required answer is

= \: (a²+ab-4b) + ( b²+4b-ab) + (c²+4a-4b)=(a²+ab−4b)+(b²+4b−ab)+(c²+4a−4b)

= a²+ab-4b + b²+4b-ab + c²+4a-4b=a²+ab−4b+b²+4b−ab+c²+4a−4b

= a² + b² + c²+4a-4b=a²+b²+c²+4a−4b

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Answer 2

Answer:

a²+ab-4b + (b²+4b-ab)+ (c²+4a -4b)

= a²+ab-4b +b²+4b-ab+c²+4a-4b

= a²+b²+c²-4b+4b-4b +ab-ab+4a

= a²+b²+c²-4b+4a

I hope this is right way