Question

add is -3y²+10y-96;7y²+8​

Answer 1

Answer:

Solution :-

❂ (- 3y² + 10y - 96) + (7y² + 8)

➻ - 3y² + 10y - 96 + 7y² + 8

➻ - 3y² + 7y² + 10y - 96 + 8

➻ 4y² + 10y - 88

➻ 2(2y² + 5y - 44)

∴ The answer of this question is 2(2y² + 5y - 44)

Answer 2

From the given question the correct answer is:

The addition of -3y²+10y-96 ; 7y²+8​    is 2(2y²+5y+44)

Given:

-3y²+10y-96;7y²+8​

To find:

addition of -3y²+10y-96;7y²+8​

Solution:

we have to add -3y²+10y-96;7y²+8​

so ,

-3y²+10y-96

7y²+8​

we can write the equation like

7y²+0y+8

as 0y=0

now we add

so we get,

= -3y²+10y-96+7y²+0y+8

=4y²+10y-88

we can take out 2 as a common

=2(2y²+5y+44)

Hence, The addition of -3y²+10y-96;7y²+8​ is 2(2y²+5y+44).