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(2d³-6a²+3d-3) and (d²-5d)
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Wrong question!!!
Correct one : (2d³-6d²+3d-3) and (d²-5d)
= ( 2d³ – 6d²+ 3d – 3 ) + ( d² – 5d )
= 2d³ + ( d² – 6d² ) + ( 3d – 5d ) – 3
= 2d³ – 5d² – 2d – 3
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