Math, asked by Aditya987, 1 year ago

add pq+qr,qr+rs,rs+ pq

Answers

Answered by KanikAb
5
pq+qr+qr+rs+rs+pq

=2pq+2qr+2rs

=2(pq+qr+rs)
Answered by pulakmath007
0

Adding pq + qr , qr + rs , rs + pq we get 2(pq + qr + rs)

Given :

The expressions pq + qr , qr + rs , rs + pq

To find :

Add the expressions

Solution :

Step 1 of 2 :

Write down the given expressions

Here the given expressions are pq + qr , qr + rs , rs + pq

Step 2 of 2 :

Add the expressions

Adding pq + qr , qr + rs , rs + pq we get

\displaystyle \sf  (pq + qr ) + ( qr + rs ) + ( rs + pq)

\displaystyle \sf   = pq + qr + qr + rs  +  rs + pq

\displaystyle \sf   = pq + pq + qr + qr + rs + rs

\displaystyle \sf   = 2pq + 2qr + 2 rs

\displaystyle \sf   = 2(pq + qr +  rs)

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