Math, asked by gayathiria150, 1 month ago

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 4\sqrt{5}  - 3 \sqrt{3}  + 4 \sqrt{3 }  - 3 \sqrt{5}  +  \sqrt{27}  - 4 \sqrt{2}

Answers

Answered by sarveshaingale08
0

Answer:

4 \sqrt{5}  - 3 \sqrt{3}  + 4 \sqrt{3}  - 3 \sqrt{5}  +  \sqrt{27}  - 4 \sqrt{2}  \\  = 4 \sqrt{5}  - 3 \sqrt{5}  - 3 \sqrt{3} 4 \sqrt{3}  +  \sqrt{27}  - 4 \sqrt{2}  \\  =  \sqrt{5}  +  \sqrt{3}  +  \sqrt{27}  - 4 \sqrt{2}  \\  =  \sqrt{5}  +  \sqrt{3 }  +  \sqrt{9 \times 3}  - 4 \sqrt{2}  \\  =  \sqrt{5}  +  \sqrt{3}  + 3 \sqrt{3}  - 4 \sqrt{2}  \\  =  \sqrt{5} + 4 \sqrt{3}   - 4 \sqrt{2}

therefore answer is

 \sqrt{5}  + 4 \sqrt{3}  - 4 \sqrt{2}

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